Errors in Physical Quantities
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The radius of a sphere is expressed as 110.4 ± 0.2 cm Find the percentage error in a) radius
b) surface area c) volume
a) Percentage error = (Δx/x)×100
•••percentage error in radius= (0.2/110.4) x 100 =0.18%
b) Surface area = 4 πr2
( derivation for the expression will be posting using calculus soon)
c) Volume = 4/3(πr3)
•••percentage error in volume= 3× Percentage error in radius=3×0.18=0.54%
Prepared by Sai’s Classes Poonkunnam Thrissur +919846088761
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