Errors in Physical Quantities

Notes on this topic is available on the home page link
The radius of a sphere is expressed as 110.4 ± 0.2 cm Find the percentage error in   a) radius
 b) surface area   c) volume
a) Percentage error = (Δx/x)×100
•••percentage error in radius= (0.2/110.4) x 100 =0.18%

b) Surface area = 4 πr2
•••percentage error in Surface area= 2× Percentage error in radius=2×0.18=0.36%
( derivation for the expression will be posting  using calculus soon)

c) Volume = 4/3(πr3)
•••percentage error in volume= 3× Percentage error in radius=3×0.18=0.54%

Prepared by Sai’s Classes Poonkunnam Thrissur +919846088761

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