Errors in Physical Quantities
Notes on this topic is available on the home page link The radius of a sphere is expressed as 110.4 ± 0.2 cm Find the percentage error in a) radius b) surface area c) volume a) Percentage error = ( Δx/x )×100 • • • percentage error in radius= (0.2/110.4) x 100 = 0.18% b) Surface area = 4 πr 2 • • • percentage error in Surface area = 2 × Percentage error in radius=2×0.18= 0.36% ( derivation for the expression will be posting using calculus soon) c) Volume = 4/3(πr 3 ) • • • percentage error in volume = 3 × Percentage error in radius=3×0.18= 0.54% Prepared by Sai’s Classes Poonkunnam Thrissur +919846088761