Displacement Current
A 50 HZ ,300 V ac is supplied to a capacitor of 1`mu`F.Calculate the displacement current. Answer: `I_d`=`epsilon_0frac{dphi_E}{dt}` `phi_E=frac{q}{epsilon_0}` `therefore``I_d`=`epsilon_0frac{d}{dt}(frac{q}{epsilon_0})` =`epsilon_0frac{d}{dt}(frac{CV}{epsilon_0})` =`Cfrac{dV}{dt}`= `C frac{d}{dt}(vsin omega t)`=`C v omega cos omega t` `omega=2pif=314` substituting `I_d`=`10^-6 times 300 times 314 cos314t` `I_d=0.942 cos(314t)`