Displacement Current
A 50 HZ ,300 V ac is supplied to a capacitor of 1μF.Calculate the displacement current.
Answer:
Id=ε0dϕEdt
ϕE=qε0 ∴Id=ε0ddt(qε0)
=ε0ddt(CVε0)
=CdVdt= Cddt(vsinωt)=Cvωcosωt
ω=2πf=314
substituting
Id=10-6×300×314cos314t
Id=0.942cos(314t)
Answer:
Id=ε0dϕEdt
ϕE=qε0 ∴Id=ε0ddt(qε0)
=ε0ddt(CVε0)
=CdVdt= Cddt(vsinωt)=Cvωcosωt
ω=2πf=314
substituting
Id=10-6×300×314cos314t
Id=0.942cos(314t)
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