Displacement Current
A 50 HZ ,300 V ac is supplied to a capacitor of 1`mu`F.Calculate the displacement current.
Answer:
`I_d`=`epsilon_0frac{dphi_E}{dt}`
`phi_E=frac{q}{epsilon_0}` `therefore``I_d`=`epsilon_0frac{d}{dt}(frac{q}{epsilon_0})`
=`epsilon_0frac{d}{dt}(frac{CV}{epsilon_0})`
=`Cfrac{dV}{dt}`= `C frac{d}{dt}(vsin omega t)`=`C v omega cos omega t`
`omega=2pif=314`
substituting
`I_d`=`10^-6 times 300 times 314 cos314t`
`I_d=0.942 cos(314t)`
Answer:
`I_d`=`epsilon_0frac{dphi_E}{dt}`
`phi_E=frac{q}{epsilon_0}` `therefore``I_d`=`epsilon_0frac{d}{dt}(frac{q}{epsilon_0})`
=`epsilon_0frac{d}{dt}(frac{CV}{epsilon_0})`
=`Cfrac{dV}{dt}`= `C frac{d}{dt}(vsin omega t)`=`C v omega cos omega t`
`omega=2pif=314`
substituting
`I_d`=`10^-6 times 300 times 314 cos314t`
`I_d=0.942 cos(314t)`
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