Friction on Moving blocks

Find the accelaration of block and force of friction  (figure) if coeficent of dynamic friction=0.1
The forces acting on the blocks are obtained by resolving the 20√2 N in to horizontal and vertical components
FH=20√2 cos45 =20 (in the direction of motion)
FV=20√2 sin45 =20( in the direction of reaction)
Weight of block=6kg=60N
Frictional force fk=μR=0.1×(60- FV)=0.1×(60-20)=4N
so the net force which causes the accelaration= FH - 4= 20 - 4 =16N

accelaration=Net force / mass= 16/6=8/3 m/sec2

Prepared by Sai’s Classes Poonkunnam Thrissur +919846088761
 

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