JEE Main Physics QNo:3 2020 (Solution)

 A bead of mass m stays at point P(a,b) on a wire bent in the shape of a parabola y=4Cx2

and rotating with angular speed 𝝎.Find the value of 𝝎.

 
 
 

Solution: Since the path of the bead is a parabola it's velocity at P can be calculated using

V=√2gh(in a projectile motion vertical motion is equivalent to free fall)

here h=b ∴--------------(1)

since y=4Cx^2

here x=a and y=b thereforeb=4Ca^2

substituting in (1)

V=sqrt(2g4ca^2)

V=2a sqrt(2gc)

𝝎=V/r here r=a

𝝎=2sqrt(2gc) (Answer)



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