It is my first post i am trying to post some of the questions and solutions for science and maths
Today's Question
If the position time relations is given by the expression x(t)=2t 3 + 5t 2 then find the velocity and accelaration at t=2 sec also comment is the velocity of the particle zero at any instant
velocity v = dx/dt v=d( 2t 3 + 5t 2 )/dt
v=6t 2 +10t
Velocity at t=2 sec
v=6x4+10x2
velocity =24+20= 44 units
accelaration=d 2 x/dt 2 =dv/dt= 12 x t+10at t=2 sec
accelaration =24+10= 34 units
If velocity=0 then6t 2 +10t=0
ie t(6t+10)=0
ie at t=0 or 6t+10=0
6t=-10
t=-10/6
Since time can not be negative . . . velocity is zero at t=0
ie at the start only