SAI'S SCIENCE AND MATHS CLASSES

Electric field on the surface of a Spherical Shell Two spherical shells of same surface charge density but the radius in the ratio 1: 2 What is the ratio of electric fields on the surface of the spherical shell E=(1/4πε 0 )q/r 2 On the surface of the sphere r=R (radius of the shell) • • • E=(1/4πε 0 )q/R 2 But q=σA (σ=surface charge density and A=surface area=4πR 2 ) • • • E=(1/4πε 0 ) σ 4πR 2 /R 2  ie E=σ/ ε 0 On the surface of the shell, E is independent of radius of the shell but depends  on the surface charge density In this case the surface charge density is the same so ratio of E on the surface is 1: 1 Prepared by Sai’s Classes Poonkunnam Thrissur +919846088761